Janusz Dziemidowicz has been making some nifty progress with his mlbms program for mounting game resource archive format (GRAF) files. Check this out:

$ mlbms bms/alg-lib.bms resource-files/alg-lib/maddog.lib mount/
$ ls -al mount/
total 1
dr-xr-xr-x  2 melanson users       0 Feb 26 23:05 .
drwxr-xr-x  7 melanson users    1120 Feb 26 19:07 ..
-r--r--r--  1 melanson users  305172 Feb 26 23:05 alg.mm
-r--r--r--  1 melanson users   24912 Feb 26 23:05 credits.mm
-r--r--r--  1 melanson users  314245 Feb 26 23:05 ibmlogo.mm
-r--r--r--  1 melanson users  338277 Feb 26 23:05 scen110a.mm
-r--r--r--  1 melanson users  278177 Feb 26 23:05 scen112a.mm
[... ad nauseum ...]

Slick, huh? I knew you’d think so. This command mounts the LIB GRAF from Mad Dog McCree as part of the normal filesystem.

Read the rest of this entry »

Pickover came through with a slightly more involved brute force challenge. As usual I’ll spare you the flowery setup (though I did find it curious that it involved a character named Ben trying to reach one named Jennifer) and distill the essential details. Given this graph of values:

 1  2  3  4  5
 6  7  8  9 10
11 12 13 14 15
16 17 18 19 20
21 22 23 24 25

find a path from any square in column 1 to any square in column 5, moving up, down, left, or right, such that the sum of all squares traversed tallies 90.

I liked writing this program because it is the most algorithmically interesting thing I have done in a long time, even though I originally solved the wrong problem. The way I originally read the problem, the task was to move from node 1 -> node 5, traversing up, down, left, or right, and find a path where the values sum to 90.

Read the rest of this entry »

Pickover’s puzzle for the weekend of February 4-5 challenged the reader to find 8 numbers to stand in for the letters D, E, G, M, N, O, R, and S such that the equation SEND + MORE = GEESE would be true. Again, there are multiple solutions. I’m pleased to report that I found 3 orders of magnitude more solutions than the big brain himself.

Read the rest of this entry »

Cliff Pickover’s puzzle from 2006-02-22 queries the reader to come up with 3 pairs, or possibly more, of numbers, m and n, which satisfy the equation n! + 1 = m². I didn’t think too hard about it. I just went straight to code which turned out to be a good thing because one of the solutions is quite large. Click more to see the reasoning I went through and the solutions output from my program.

Read the rest of this entry »